Exterior derivative
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In differential geometry, the exterior derivative extends the concept of the differential of a function, which is a form of degree zero, to differential forms of higher degree. Its current form was invented by Élie Cartan.
The exterior derivative d has the property that d2 = 0 and is the differential (coboundary) used to define de Rham (and Alexander-Spanier) cohomology on forms. Integration of forms gives a natural homomorphism from the de Rham cohomology to the singular cohomology of a smooth manifold. The theorem of de Rham shows that this map is actually an isomorphism. In this sense, the exterior derivative is the "dual" of the boundary map on singular simplices.
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[edit] Definition
The exterior derivative of a differential form of degree k is a differential form of degree k + 1.
Given a multi-index
with
the exterior derivative of a k-form
where
over Rn is defined as
For general k-forms ω = ΣI fI dxI (where the components of the multi-index I run over all the values in {1, ..., n}), the definition of the exterior derivative is extended linearly. Note that whenever i is one of the components of the multi-index I, then
(see wedge product).
Geometrically, the k + 1 form dω acts on each tangent space of Rn in the following way: a (k + 1)-tuple of vectors (u1,...,uk + 1) in the tangent space defines an oriented (k + 1)-polyhedron p. Then dω(u1,...,uk + 1) is defined to be the integral of ω over the boundary of p, where the boundary is given the inherited orientation. Assuming the fact that every smooth manifold admits a (smooth) triangulation, this gives immediately Stokes' theorem.
[edit] Alternative definition
The exterior derivative of a differential form of degree k is again a differential form of degree k + 1, with the following properties:
for smooth functions (zero-forms)- d(x + y) = dx + dy


we can easily obtain the previous definition:
we have here interpreted fI as a zero-form, and then applied the properties of the exterior derivative.
[edit] Examples
[edit] 1
Consider
over a 1-form basis
. The exterior derivative is:
The last formula follows easily from the properties of the wedge product.
[edit] 2
For a 1-form
on R2 we have, by applying the above formula to each term (consider x1 = x and x2 = y in the following sum),
[edit] Properties
Exterior differentiation is by definition linear. Direct computation shows that it also has the following properties:
- the wedge product rule holds (see antiderivation)
- and d2 = 0, which follows from the equality of mixed partial derivatives.
It can be shown that the exterior derivative is uniquely determined by these properties and its agreement with the differential on 0-forms (functions).
Differential forms in the kernel of d are said to be closed forms. For instance, a 1-form is closed if on each tangent space, its integral along the boundary of the parallelogram given by any pair of tangent vectors is zero. Thus closedness is a local condition. The image of d is said to consist of exact forms (cf. exact differentials). It is immediate that exact forms are closed.
The exterior derivative is natural. If f: M → N is a smooth map and Ωk is the contravariant smooth functor that assigns to each manifold the space of k-forms on the manifold, then the following diagram commutes
so d(f*ω) = f*dω, where f* denotes the pullback of f. This follows from that f*ω(·), by definition, is ω(f*(·)), f* being the pushforward of f. Thus d is a natural transformation from Ωk to Ωk+1.
[edit] Invariant formula
Given a k-form ω and arbitrary smooth vector fields V0,V1, …, Vk we have
where [Vi,Vj] denotes Lie bracket and the hat denotes the omission of that element: 
In particular, for 1-forms we have:
- dω(X,Y) = X(ω(Y)) − Y(ω(X)) − ω([X,Y]).
[edit] The exterior derivative in calculus
The following correspondence reveals about a dozen formulas from vector calculus as merely special cases of the above three rules of exterior differentiation.
[edit] Gradient
For a 0-form, that is, a smooth function f: Rn→R, we have
This is a 1-form, a section of the cotangent bundle, that gives local linear approximation to f on each tangent space.
For a vector field V,
where grad f denotes gradient of f and < , > is the scalar product.
[edit] Curl
One can associate to a vector field V = (u, v, w) on R3 the 1-form
and the 2-form
The integral of ω1V over a path gives work done against -V along the path; locally, it is the dot product with V. The integral of ω2V over a surface gives the flux of V over that surface; locally, it is the scalar triple product with V.
One can check directly that
where curl V denotes the curl of V. The flux of curl V over a surface is the integral of ω1V over the boundary of the surface.
[edit] Divergence
Similarly,
The flux of V over the boundary of a 3-polyhedron p is given by the integral of the divergence of V over p.
[edit] Invariant formulations of grad, curl, and div
The three operators above can be written in coordinate-free notation as follows:
where
is the Hodge star operator and
and
are the musical isomorphisms.
[edit] See also
[edit] References
- Flanders, Harley (1989). Differential forms with applications to the physical sciences. New York: Dover Publications. pp. 20. ISBN 0-486-66169-5.
- Ramanan, S. (2005). Global calculus. Providence, Rhode Island: American Mathematical Society. pp. 54. ISBN 0-8218-3702-8.
- Conlon, Lawrence (2001). Differentiable manifolds. Basel, Switzerland: Birkhäuser. pp. 239. ISBN 0-8176-4134-3.
- Darling, R. W. R. (1994). Differential forms and connections. Cambridge, UK: Cambridge University Press. pp. 35. ISBN 0-521-46800-0.
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![+\sum_{i<j}(-1)^{i+j}\omega([V_i, V_j], V_0, \ldots, \hat V_i, \ldots, \hat V_j, \ldots, V_k)](http://upload.wikimedia.org/math/6/4/a/64a21f413a45ec9d68ad42081d1323b6.png)






![\begin{array}{rcl}
\nabla f &=& \left( {\mathbf d} f \right)^\sharp \\
\nabla \times F &=& \left[ \star \left( {\mathbf d} F^\flat \right) \right]^\sharp \\
\nabla \cdot F &=& \star {\mathbf d} \left( \star F^\flat \right) \\
\end{array}](http://upload.wikimedia.org/math/f/f/d/ffd7bfba50b8060ad34f026c044b35bf.png)